QUESTIONS ON REASONING (PART-8)

Most of these questions are taken from the previous examinations conducted by the Staff Selection Commission (SSC) of the General Intelligence and Reasoning section of the following exams as well as other similar exams. They are all solved and supported by detailed explanation.

1. Combined Graduate Level (CGL) Exam Tier-I

2. Combined Higher Secondary (10+2) Exam (CHSL) Tier-I

3. SI in Delhi Police and CPO Exam Tier-I

4. Stenographers Exam

5. Grade-II DASS Exam conducted by Delhi Staff Subordinate Services (DSSSB)

QUERY 141

3        4       6
5        7       3
1        2       7
35   69      ?

MAHA GUPTA
Sum of the squares of the first three number is equal to the fourth number in each column; see how
3^2 + 5^2 + 1^2 = 35
4^2 + 7^2 + 2^2 = 69

Therefore the required number
6^2 + 3^2 + 7^2 = 94 (answer)

QUERY 142

251 (12) 107
381 (_) 125

14
24
16
11

MAHA GUPTA
251 – 107 = 144; root144 = 12

Similarly the required number
381 – 125 = 256; root 256 = 16 (option ‘3’)

QUERY 143

9 + 3 = 722
5 + 7 = 536
8 + 6 = 845
4 + 4 = 613
then
7 + 2=?

MAHA GUPTA
Reverse the digits of the product of the numbers on LHS and put the digit less than 1 of the second number on unit’s place to get the number on RHS; see how

9*3 = 27, 72, 3 -1 = 2; so RHS = 722
5*7 = 35, 53, 7 – 6 = 6; so RHS = 536
8*6 = 48, 84, 6 – 1 = 5; so RHS = 845
4*4 = 16, 61, 4 – 1 = 3; so RHS = 613

Therefore the required number
7*2 = 14, 41, 2 – 1 = 1; so RHS = 411 (answer)

QUERY 144

MAHA GUPTA

Deduct the sum of squares of the numbers from the cube of the number in the bracket; see how
3^3 – (1^2 + 4^2) = 27 – 17 = 10
4^3 – (3^2 + 6^2) = 64 – 45 = 19

Therefore the required number
5^3 – (4^2 + 7^2) = 125 – 65 = 60 (option ‘3’)

QUERY 145

583 : 293 :: 488 : ?

291
378
487
581

SJ PATEL
378 (option ‘2’)
The sum of digits is decreasing by 2; see how
LHS
5+8+3 = 16
2+9+3 = 14

RHS
4+8+8 = 20
So we need a number the sum of whose digits is 20 – 2 = 18
We see out of the given options only 378 is such a number

QUERY 146

9 : 7 :: 80 : ?

48
50
78
82

MAHA GUPTA
78 (option ‘C’)
LHS
9 – 2 = 7

RHS
Therefore the required number = 80 – 2 = 78

Plz note that in analogy the relation between the terms on LHS is seen or relation between the terms on RHS; you can’t establish relation between one term of LHS and one term of RHS. The question 9 : 80 :: 7 : ? is different. In this question the answer will be 48 as
LHS
9^2 – 1 = 80

RHS
7^2 – 1 48

QUERY 147

Similar set of 1, 5, 12 is?

7, 11, 35
4, 8, 24
10, 14, 44
9, 13, 42

MAHA GUPTA
The second number is more by four of the first; the third number is twice of the sum of first and second.

Therefore the answer is 4, 8, 24 (option ‘2’).

QUERY 148

0, 2, 10, 30, ?

KUMAR SAURABH
Every number is cube of a consecutive whole number starting from 0 plus the number itself; see how
0^3 + 0 = 0
1^3 + 1 = 2
2^3 + 2 = 10
3^3 + 3 = 30

Therefore the required number
4^3 + 4 = 68

QUERY 149

Wrong number in the sequence?
102, 101, 98, 93, 86, 74, 66, 53

101
66
74
93

MAHA GUPTA
Numbers are in decreasing order by consecutive odd numbers from the beginning; see how
102 – 1 = 101
101 – 3 = 98
98 – 5 = 93
93 – 7 = 86
86 – 9 = 77 ; so the culprit is 74 (option ‘3’)
77 – 11 = 66
66 – 13 = 53

QUERY 150

9×7 = 32
13×7 = 120
17×9 = 208
19×11 = ?

MAHA GUPTA
Multiply the addition and subtraction of the numbers on LHS to get RHS; see how
(9 + 7)*(9 – 7) = 32
(13 + 7)*(13 – 7) = 120
(17 + 9)*(17 – 9) = 208

So the required number
(19 + 11)*(19 – 11) = 240 (answer)

QUERY 151

4, 18, 48, ?, 180

80
100
105
125

MAHA GUPTA
The pattern is n(n+1)^2; where n is a consecutive natural number from 1 itself; see how
1*(1 +1)^2 = 4
2*(2 + 1)^2 = 18
3*(3 + 1)^2 = 48
So the required number = 4*(4+1)^2 = 100 (option ‘2’)

5*(5 + 1) = 180

NOTE: You can see this pattern like this also
1*2^2 = 4
2*3^2 = 18
3*4^2 = 48
4*5^2 = 100
5*6^2 = 180

QUERY 152

4, 13, 38, ?

MAHA GUPTA
Pattern is
4*3^0 + 0 = 4
4*3^1 + 1 = 13
4*3^2 + 2 = 38

Therefore the required number
4*3^3 + 3 = 111 (answer)

NOTE: This is reasoning; in which a logic differs from options to options. But here no options are given; it’s just my view.

QUERY 153

423 : 657:: 534 : ?

678
867
768
876

MAHA GUPTA
LHS
423 + 234 = 657

So the required number
534 +234 = 768 (option ‘C’)

QUERY 154

5, 39, 272, 1631, ?

MAHA GUPTA
5*8 = 40; 40 – 1 = 39
39*7 = 273; 273 – 1 = 272
272*6 = 1632; 1632 – 1 = 1631

Therefore the required number
1631*5 = 8155; 8155 – 1 = 8154 (answer)

QUERY 155

7×2 = 28
6×3 = 36
then 4×4 = ?

MAHA GUPTA
PATTERN
7*(2+2) = 28
6*(3+3) = 36

Therefore the required number
4*(4+4) = 32 (answer)

QUERY 156

123 = 14, 323 = 22, 624 = ?

SUMIT BISLA
Add the squares of all the digit of LHS
1^2 + 2^2 + 3^2 = 14
3^2 + 2^2 + 3^2 = 22
Therefore the required number
6^2 + 2^2 + 4^2 = 56 (answer)

QUERY 157

TSAE : TSEW::HTRON : ?

HTUSO
HTUOS
HTOUS
HTSOU

MUKESH NAYAK
Relation between the terms of LHS is that they are reverse in order of the names of directions; see how
LHS
TSAE => EAST
TSEW => WEST

RHS
HTRON => NORTH

So it will be reverse of SOUTH i.e. HTUOS (option ‘2’)

QUERY 158

Doctor : Patient :: ?

Crop : Farmer,
Engineer : Computer,
Lawyer : Judge,
Pilot : Plane

MAHA GUPTA
ENGINEER : COMPUTER (option ‘2’)
As a doctor treats/repairs a patient, an engineer repairs a machine.

In one of the meanings ENGINEER = a person who is trained to repair machines and electrical equipment.

QUERY 159

4, 11, 30, 85, 248, ?

333
444
683
735

MAHA GUPTA
Pattern
3^1 + 1 = 4
3^2 + 2 = 11
3^3 + 3 = 30
3^4 + 4 = 85
3^5 + 5 = 248

Therefore the required number
3^6 + 6 = 735 (option ‘4’)

QUERY 160

Find odd pair
120 – 80
57 – 19
45 – 30
63 – 42

MAHA GUPTA
57 – 19 (option ‘2’)
In all other pairs the first number is half more than the second.