QUESTIONS ON REASONING (PART-8)
QUESTIONS ON REASONING (PART-8)
QUERY 141
3 4 6
5 7 3
1 2 7
35 69 ?
MAHA GUPTA
Sum of the squares of the first three number is equal to the fourth number in each column; see how
3^2 + 5^2 + 1^2 = 35
4^2 + 7^2 + 2^2 = 69
Therefore the required number
6^2 + 3^2 + 7^2 = 94 (answer)
QUERY 142
251 (12) 107
381 (_) 125
14
24
16
11
MAHA GUPTA
251 – 107 = 144; root144 = 12
Similarly the required number
381 – 125 = 256; root 256 = 16 (option ‘3’)
QUERY 143
9 + 3 = 722
5 + 7 = 536
8 + 6 = 845
4 + 4 = 613
then
7 + 2=?
MAHA GUPTA
Reverse the digits of the product of the numbers on LHS and put the digit less than 1 of the second number on unit’s place to get the number on RHS; see how
9*3 = 27, 72, 3 -1 = 2; so RHS = 722
5*7 = 35, 53, 7 – 6 = 6; so RHS = 536
8*6 = 48, 84, 6 – 1 = 5; so RHS = 845
4*4 = 16, 61, 4 – 1 = 3; so RHS = 613
Therefore the required number
7*2 = 14, 41, 2 – 1 = 1; so RHS = 411 (answer)
QUERY 144
MAHA GUPTA
Deduct the sum of squares of the numbers from the cube of the number in the bracket; see how
3^3 – (1^2 + 4^2) = 27 – 17 = 10
4^3 – (3^2 + 6^2) = 64 – 45 = 19
Therefore the required number
5^3 – (4^2 + 7^2) = 125 – 65 = 60 (option ‘3’)
QUERY 145
583 : 293 :: 488 : ?
291
378
487
581
SJ PATEL
378 (option ‘2’)
The sum of digits is decreasing by 2; see how
LHS
5+8+3 = 16
2+9+3 = 14
RHS
4+8+8 = 20
So we need a number the sum of whose digits is 20 – 2 = 18
We see out of the given options only 378 is such a number
QUERY 146
9 : 7 :: 80 : ?
48
50
78
82
MAHA GUPTA
78 (option ‘C’)
LHS
9 – 2 = 7
RHS
Therefore the required number = 80 – 2 = 78
Plz note that in analogy the relation between the terms on LHS is seen or relation between the terms on RHS; you can’t establish relation between one term of LHS and one term of RHS. The question 9 : 80 :: 7 : ? is different. In this question the answer will be 48 as
LHS
9^2 – 1 = 80
RHS
7^2 – 1 48
QUERY 147
Similar set of 1, 5, 12 is?
7, 11, 35
4, 8, 24
10, 14, 44
9, 13, 42
MAHA GUPTA
The second number is more by four of the first; the third number is twice of the sum of first and second.
Therefore the answer is 4, 8, 24 (option ‘2’).
QUERY 148
0, 2, 10, 30, ?
KUMAR SAURABH
Every number is cube of a consecutive whole number starting from 0 plus the number itself; see how
0^3 + 0 = 0
1^3 + 1 = 2
2^3 + 2 = 10
3^3 + 3 = 30
Therefore the required number
4^3 + 4 = 68
QUERY 149
Wrong number in the sequence?
102, 101, 98, 93, 86, 74, 66, 53
101
66
74
93
MAHA GUPTA
Numbers are in decreasing order by consecutive odd numbers from the beginning; see how
102 – 1 = 101
101 – 3 = 98
98 – 5 = 93
93 – 7 = 86
86 – 9 = 77 ; so the culprit is 74 (option ‘3’)
77 – 11 = 66
66 – 13 = 53
QUERY 150
9×7 = 32
13×7 = 120
17×9 = 208
19×11 = ?
MAHA GUPTA
Multiply the addition and subtraction of the numbers on LHS to get RHS; see how
(9 + 7)*(9 – 7) = 32
(13 + 7)*(13 – 7) = 120
(17 + 9)*(17 – 9) = 208
So the required number
(19 + 11)*(19 – 11) = 240 (answer)
QUERY 151
4, 18, 48, ?, 180
80
100
105
125
MAHA GUPTA
The pattern is n(n+1)^2; where n is a consecutive natural number from 1 itself; see how
1*(1 +1)^2 = 4
2*(2 + 1)^2 = 18
3*(3 + 1)^2 = 48
So the required number = 4*(4+1)^2 = 100 (option ‘2’)
5*(5 + 1) = 180
NOTE: You can see this pattern like this also
1*2^2 = 4
2*3^2 = 18
3*4^2 = 48
4*5^2 = 100
5*6^2 = 180
QUERY 152
4, 13, 38, ?
MAHA GUPTA
Pattern is
4*3^0 + 0 = 4
4*3^1 + 1 = 13
4*3^2 + 2 = 38
Therefore the required number
4*3^3 + 3 = 111 (answer)
NOTE: This is reasoning; in which a logic differs from options to options. But here no options are given; it’s just my view.
QUERY 153
423 : 657:: 534 : ?
678
867
768
876
MAHA GUPTA
LHS
423 + 234 = 657
So the required number
534 +234 = 768 (option ‘C’)
QUERY 154
5, 39, 272, 1631, ?
MAHA GUPTA
5*8 = 40; 40 – 1 = 39
39*7 = 273; 273 – 1 = 272
272*6 = 1632; 1632 – 1 = 1631
Therefore the required number
1631*5 = 8155; 8155 – 1 = 8154 (answer)
QUERY 155
7×2 = 28
6×3 = 36
then 4×4 = ?
MAHA GUPTA
PATTERN
7*(2+2) = 28
6*(3+3) = 36
Therefore the required number
4*(4+4) = 32 (answer)
QUERY 156
123 = 14, 323 = 22, 624 = ?
SUMIT BISLA
Add the squares of all the digit of LHS
1^2 + 2^2 + 3^2 = 14
3^2 + 2^2 + 3^2 = 22
Therefore the required number
6^2 + 2^2 + 4^2 = 56 (answer)
QUERY 157
TSAE : TSEW::HTRON : ?
HTUSO
HTUOS
HTOUS
HTSOU
MUKESH NAYAK
Relation between the terms of LHS is that they are reverse in order of the names of directions; see how
LHS
TSAE => EAST
TSEW => WEST
RHS
HTRON => NORTH
So it will be reverse of SOUTH i.e. HTUOS (option ‘2’)
QUERY 158
Doctor : Patient :: ?
Crop : Farmer,
Engineer : Computer,
Lawyer : Judge,
Pilot : Plane
MAHA GUPTA
ENGINEER : COMPUTER (option ‘2’)
As a doctor treats/repairs a patient, an engineer repairs a machine.
In one of the meanings ENGINEER = a person who is trained to repair machines and electrical equipment.
QUERY 159
4, 11, 30, 85, 248, ?
333
444
683
735
MAHA GUPTA
Pattern
3^1 + 1 = 4
3^2 + 2 = 11
3^3 + 3 = 30
3^4 + 4 = 85
3^5 + 5 = 248
Therefore the required number
3^6 + 6 = 735 (option ‘4’)
QUERY 160
Find odd pair
120 – 80
57 – 19
45 – 30
63 – 42
MAHA GUPTA
57 – 19 (option ‘2’)
In all other pairs the first number is half more than the second.