# QUESTIONS ON REASONING (PART-8)

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#### QUESTIONS ON REASONING (PART-8)

#### QUERY 141

**3 4 6**

** 5 7 3**

** 1 2 7**

** 35 69 ?**

**MAHA GUPTA**

Sum of the squares of the first three number is equal to the fourth number in each column; see how

3^2 + 5^2 + 1^2 = 35

4^2 + 7^2 + 2^2 = 69

Therefore the required number

6^2 + 3^2 + 7^2 = 94 (answer)

QUERY 142

**251 (12) 107**

** 381 (_) 125**

14

24

16

11

**MAHA GUPTA**

251 – 107 = 144; root144 = 12

Similarly the required number

381 – 125 = 256; root 256 = 16 (option ‘3’)

QUERY 143

**9 + 3 = 722**

** 5 + 7 = 536**

** 8 + 6 = 845**

** 4 + 4 = 613**

** then**

** 7 + 2=?**

**MAHA GUPTA**

Reverse the digits of the product of the numbers on LHS and put the digit less than 1 of the second number on unit’s place to get the number on RHS; see how

9*3 = 27, 72, 3 -1 = 2; so RHS = 722

5*7 = 35, 53, 7 – 6 = 6; so RHS = 536

8*6 = 48, 84, 6 – 1 = 5; so RHS = 845

4*4 = 16, 61, 4 – 1 = 3; so RHS = 613

Therefore the required number

7*2 = 14, 41, 2 – 1 = 1; so RHS = 411 (answer)

QUERY 144

**MAHA GUPTA**

Deduct the sum of squares of the numbers from the cube of the number in the bracket; see how

3^3 – (1^2 + 4^2) = 27 – 17 = 10

4^3 – (3^2 + 6^2) = 64 – 45 = 19

Therefore the required number

5^3 – (4^2 + 7^2) = 125 – 65 = 60 (option ‘3’)

QUERY 145

**583 : 293 :: 488 : ?**

291

378

487

581

**SJ PATEL**

378 (option ‘2’)

The sum of digits is decreasing by 2; see how

LHS

5+8+3 = 16

2+9+3 = 14

RHS

4+8+8 = 20

So we need a number the sum of whose digits is 20 – 2 = 18

We see out of the given options only 378 is such a number

QUERY 146

**9 : 7 :: 80 : ?**

48

50

78

82

**MAHA GUPTA**

78 (option ‘C’)

LHS

9 – 2 = 7

RHS

Therefore the required number = 80 – 2 = 78

Plz note that in analogy the relation between the terms on LHS is seen or relation between the terms on RHS; you can’t establish relation between one term of LHS and one term of RHS. The question 9 : 80 :: 7 : ? is different. In this question the answer will be 48 as

LHS

9^2 – 1 = 80

RHS

7^2 – 1 48

QUERY 147

**Similar set of 1, 5, 12 is?**

7, 11, 35

4, 8, 24

10, 14, 44

9, 13, 42

**MAHA GUPTA**

The second number is more by four of the first; the third number is twice of the sum of first and second.

Therefore the answer is 4, 8, 24 (option ‘2’).

QUERY 148

**0, 2, 10, 30, ?**

**KUMAR SAURABH**

Every number is cube of a consecutive whole number starting from 0 plus the number itself; see how

0^3 + 0 = 0

1^3 + 1 = 2

2^3 + 2 = 10

3^3 + 3 = 30

Therefore the required number

4^3 + 4 = 68

QUERY 149

**Wrong number in the sequence?**

** 102, 101, 98, 93, 86, 74, 66, 53**

101

66

74

93

**MAHA GUPTA**

Numbers are in decreasing order by consecutive odd numbers from the beginning; see how

102 – 1 = 101

101 – 3 = 98

98 – 5 = 93

93 – 7 = 86

86 – 9 = 77 ; so the culprit is 74 (option ‘3’)

77 – 11 = 66

66 – 13 = 53

QUERY 150

**9×7 = 32**

** 13×7 = 120**

** 17×9 = 208**

** 19×11 = ?**

**MAHA GUPTA**

Multiply the addition and subtraction of the numbers on LHS to get RHS; see how

(9 + 7)*(9 – 7) = 32

(13 + 7)*(13 – 7) = 120

(17 + 9)*(17 – 9) = 208

So the required number

(19 + 11)*(19 – 11) = 240 (answer)

QUERY 151

**4, 18, 48, ?, 180**

80

100

105

125

**MAHA GUPTA**

The pattern is n(n+1)^2; where n is a consecutive natural number from 1 itself; see how

1*(1 +1)^2 = 4

2*(2 + 1)^2 = 18

3*(3 + 1)^2 = 48

So the required number = 4*(4+1)^2 = 100 (option ‘2’)

5*(5 + 1) = 180

NOTE: You can see this pattern like this also

1*2^2 = 4

2*3^2 = 18

3*4^2 = 48

4*5^2 = 100

5*6^2 = 180

QUERY 152

**4, 13, 38, ?**

**MAHA GUPTA**

Pattern is

4*3^0 + 0 = 4

4*3^1 + 1 = 13

4*3^2 + 2 = 38

Therefore the required number

4*3^3 + 3 = 111 (answer)

NOTE: This is reasoning; in which a logic differs from options to options. But here no options are given; it’s just my view.

QUERY 153

**423 : 657:: 534 : ?**

678

867

768

876

**MAHA GUPTA**

LHS

423 + 234 = 657

So the required number

534 +234 = 768 (option ‘C’)

QUERY 154

**5, 39, 272, 1631, ?**

**MAHA GUPTA**

5*8 = 40; 40 – 1 = 39

39*7 = 273; 273 – 1 = 272

272*6 = 1632; 1632 – 1 = 1631

Therefore the required number

1631*5 = 8155; 8155 – 1 = 8154 (answer)

QUERY 155

**7×2 = 28**

** 6×3 = 36**

** then 4×4 = ?**

**MAHA GUPTA**

PATTERN

7*(2+2) = 28

6*(3+3) = 36

Therefore the required number

4*(4+4) = 32 (answer)

QUERY 156

**123 = 14, 323 = 22, 624 = ?**

**SUMIT BISLA**

Add the squares of all the digit of LHS

1^2 + 2^2 + 3^2 = 14

3^2 + 2^2 + 3^2 = 22

Therefore the required number

6^2 + 2^2 + 4^2 = 56 (answer)

QUERY 157

**TSAE : TSEW::HTRON : ?**

HTUSO

HTUOS

HTOUS

HTSOU

**MUKESH NAYAK**

Relation between the terms of LHS is that they are reverse in order of the names of directions; see how

LHS

TSAE => EAST

TSEW => WEST

RHS

HTRON => NORTH

So it will be reverse of SOUTH i.e. HTUOS (option ‘2’)

QUERY 158

**Doctor : Patient :: ?**

Crop : Farmer,

Engineer : Computer,

Lawyer : Judge,

Pilot : Plane

**MAHA GUPTA**

ENGINEER : COMPUTER (option ‘2’)

As a doctor treats/repairs a patient, an engineer repairs a machine.

In one of the meanings ENGINEER = a person who is trained to repair machines and electrical equipment.

QUERY 159

**4, 11, 30, 85, 248, ?**

333

444

683

735

**MAHA GUPTA**

Pattern

3^1 + 1 = 4

3^2 + 2 = 11

3^3 + 3 = 30

3^4 + 4 = 85

3^5 + 5 = 248

Therefore the required number

3^6 + 6 = 735 (option ‘4’)

QUERY 160

**Find odd pair**

** 120 – 80**

** 57 – 19**

** 45 – 30**

** 63 – 42**

**MAHA GUPTA**

57 – 19 (option ‘2’)

In all other pairs the first number is half more than the second.