# QUESTIONS ON REASONING (PART-7)

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#### QUERY 121

**25 : 175 :: 32 : ?**

150

170

162

160

**MAHA GUPTA**

Sum of the digit of the first number is multiplied by the number itself to get the other number; see how

25; (2+5)*25 = 175

Therefore the required number

32; (3+2)*32 = 160 (option ‘4’)

QUERY 122

**MAHA GUPTA**

Every number of RHS is multiplied with its next number; so the answer is 3*4 = 12. It can’t be 3*6 as the sequence of earlier number i.e. 9, 8, 7, 6 is now broken.

QUERY 123

**14*13 = 128**

** 16*13 = 280**

** 15*11 = ?**

**MAHA GUPTA**

The last two digits of the multiplication of the numbers on LHS get interchanged in the number of RHS; see how

14*13 = 182; RHS = 128

16*13 = 208; RHS = 280

Therefore 15*11 = 165; RHS = 156 (answer)

QUERY 124

**Rahul Choudhry**

Product of the bottom left number to it’s diagonally opposite number is forming the number of the other diagonal; see how

6*3 = 18

7*9 = 63

6*4 = 24

Therefore the desired number

7*6 = 42; hence the digit 4 (answer).

QUERY 125

**Reepa Nimesh**

Divide the number formed by the digits at the top of the square by the number formed by the digits at the bottom; see how

85/17 = 5

76/19 = 4

So, the required number

91/13 = 7 (answer)

QUERY 126

**Reepa Nimesh**

LHS: 6 – 2 = 4; 4 – 1 = 3 and 2 + 4 = 6; 6 – 1 = 5. Thus RHS = 35

LHS: 7 – 5 = 2; 2 – 1 = 1 and 1 + 5 = 6; 6 – 1 = 5. Thus RHS = 11

LHS: 4 – 2 = 2; 2 – 1 = 1 and 1 + 1 = 2; 2 – 1 = 1. Thus RHS = 11

Likewise the required number

LHS: 7 – 1 = 6; 6 – 1 = 5 and 3 + 3 = 6; 6 – 1 = 5. Thus RHS = 55 (answer)

QUERY 127

**16, 71, 87, 158, 141, 61, 76, 137, ?**

**MAHA GUPTA**

Digit at the most left place becomes the unit’s digit of the next number, and their sum becomes the other digits of the next number

So the next number to 137 = 111 (answer)

QUERY 128

**MAHA GUPTA**

RHS = cube of the number on LHS + the number itself

So the required number = 5^3 + 5 = 130 (answer)

QUERY 129

**7, 9, 13, 21, 18, 9, -18, -14, 2, ?, ?**

**SHIV KISHOR**

(+2, +4, +8), (-3, -9, -27), (+4, +16, +64), -71

Therefore the required numbers are 66 and 71

#### QUERY 130

**Find odd number?**

** 74, 7**

** 41, 4**

** 63, 6**

** 97, 9**

**MAHA GUPTA**

Option ‘4’. The difference of the digits of the first number in each set is 3; but in the last set it is 2.

QUERY 131

**95, 115, 145, 155, ?**

185

165

215

175

**MAHA GUPTA**

185 (option ‘1’). Each number is multiplication of 5 and a prime number increasing consecutively; see how

95 = 5*19

115 = 5* 23

145 = 5*29

155 = 5*31

Therefore the next number = 5*37 = 185

QUERY 132

**445, 221, 109, ?, 25, 11, 4**

**Abhishek Tyagi**

Starting from end the sequence goes like this

4*2 + 3 = 11

11*2 + 3 = 25

25*2 + 3 = 53 (answer)

53*2 + 3 = 109

109*2 + 3 = 221

221*2 + 3 = 445

**Amrit Prakash**

The difference between two consecutive numbers stating from the end-point is increasing two times of its previous

11-4 (diff- 7)

25-11 (diff- 14)

53-25 (diff-28)

109-53 (diff-56)

221-109 (diff-112)

445-221 (diff-224)

So the required number is 53 (answer)

QUERY 133

**61, 52, 63, 94, 46, ?**

19

18

17

16

**MAHA GUPTA**

The number formed by reversing the digit of each number of the sequence is square of consecutive natural numbers starting from 4; see how

61 —- 16 = 4^2

52 —- 25 = 5^2

63 —- 36 = 6^2

94 —- 49 = 7^2

46 —- 64 = 8^2

Therefore the required number = 9^2 = 81 —- 18 (option ‘2’)

QUERY 134

**8 : 12 :: 6 : ?**

8

11

5

7

**MAHA GUPTA**

Half of 12 i.e. 6 is the key to find exact analogy here.

Taking 6 as base, LHS = 6 + 2= 8; 6*2 = 12

Means the second term of RHS is double of (the first term – 2)

So RHS = 4 + 2 = 6; 4*2 = 8 (option ‘1’)

QUERY 135

**4267 = 10**

** 3374 = 9**

** 4255 = ?**

10

12

20

8

**MAHA GUPTA**

Deduct the product of the second and fourth digits of each number from the product of the first and third digits to get RHS; see how

i) 4*6 – 2*7 = 10

ii) 3*7 – 3*4 = 9

Therefore the required number = 4*5 = 2*5 = 10 (option ‘1’)

QUERY 136

**Find odd**

Teeth

Sleep

Sheep

Greed

**MAHA GUPTA**

TEETH (option ‘1’) as the consonant ‘T’ is repeated

QUERY 137

**11 14 2 39**

** 12 15 3 57**

** 13 16 4 ?**

87

75

84

77

**MAHA GUPTA**

Multiply second and third number of every row and add the first one to it to find the last number; see how

Row-I: 14*2 + 11 = 39

Row-II: 15*3 + 12 = 57

Therefore the required number = 16*4 + 13 = 77 (option ‘4’)

QUERY 138

**Select the odd**

** Cow**

** Dog**

** Camel**

** Ox**

**MAHA GUPTA**

DOG (option ‘2’). Except DOG the others come under CATTLE. You cannot select the words here based on gender as both DOG and CAMEL refer to both male and female genders. Male DOG = dog; female dog = bitch. Male camel = bull; female CAMEL = cow

QUERY 139

**Mamta Jindal**

Addition of the squares of the number in the upper circles is equal to the number in the lower circle; see how

3^2 + 2^2 = 13

4^2 + 8^2 = 80

Likewise

1^2 + 5^2 = 26 (answer)

QUERY 140

**BOOK : PUBLISHER :: FILM : ?**

DIRECTOR

PRODUCER

WRITER

COMPOSER

**MAHA GUPTA**

PRODUCER (option ‘2’). PUBLISHER = a company or person that prepares and issues books, journals, or music for sale. PRODUCER = One who supervises and controls the finances, creation, and public presentation of a play, film, program, or similar work.

So we see both do similar kind of work.