REASONING

QUESTIONS ON REASONING (PART-2)

QUESTIONS ON REASONING (PART-2)

Most of these questions are taken from the previous examinations conducted by the Staff Selection Commission (SSC) of the General Intelligence and Reasoning section of the following exams as well as other exams. They are all solved and supported by detailed explanation.

1. Combined Graduate Level (CGL) Exam Tier-I

2. Combined Higher Secondary (10+2) Exam (CHSL) Tier-I

3. SI in Delhi Police and CPO Exam Tier-I

4. Stenographers Exam

5. Grade-II DASS Exam conducted by Delhi Staff Subordinate Services (DSSSB)

QUERY 21

13 : 19 :: 21 : ?

41
141
81
14

MAHA GUPTA
Relation between the first two terms:
1^2 & 3^2 = 19

Likewise 2^2 & 1^2 = 41 (option ‘1’)


QUERY 22

DKM, FJP, HIS, JHV, ….

LGY
HGY
IGZ
IGY

SANGEETA RATHEE
1st = 4 11 13
2nd = 6 10 16
3rd = 8 9 19
4th = 10 8 22

So the 5th = 12 7 25 = LGY (option ‘1’)


QUERY 23

85+25 = 50, 97+65 = 93, 72+94 = ?

92
50
67
60

SHIV KISHOR
1st = 8*5 + 2*5 = 50
2nd = 9*7 + 6*5 = 93

Therefore 3rd = 7*2 + 9*4 = 50


QUERY 24

11, 29, 55, …. , 131

110
81
89
78

Dibyendu Dutta
Ist: 3^2 + 2 = 11
IInd: 5^2 + 4 = 29
IIIrd: 7^2 + 6 = 55

So IVth: 9^2 + 8 = 89 (option ‘3’)

Sangeeta Rathee
89 (option ‘3’)
every time the difference increases by 8


QUERY 25

If ‘CARING’ is coded as ‘EDVGKC’, and ‘SHARES’ is coded as ‘UKEPBO’, how will CASKET be coded as in the same code?

EDXIBP
EDWIAP
EDWPAI
EDWIBP

Sangeeta Rathee
The difference is such as:
+2+3+4 -2-3-4

Therefore EDWIBP (option ‘4’) is correct.


QUERY 26

12, 32, 56, 1130, ?

15640
19760
41330
52840

Pankaj Kumar
1+2 = 3 & 1*2 = 2, so 32
3+2 = 5 & 3*2 = 6, so 56
5+6 = 11 & 5*6 = 30, so 1130
11+30 = 41 & 11*30 = 330, so, 41330


QUERY 27

If 55+66 = 33, 22+99 = 33, then 44+88 = ?

33
36
38
40

AMIT KUMAR
(5+6)*3 = 33
(2+9)*3 = 33

Therefore (4+8)*3 = 36

QUERY 28

If 62 x 3 = 30, 52 x 5 = 35, 32 x 6 = 24; then 84 x 3 = ?

MAHA GUPTA
6*(2+3) = 30
5*(2+5) = 35
3*(2+6) = 24

Therefore 8*(4+3) = 56


QUERY 29

4, 13, 38, ?

123
58
96
111

Himanshu Kathuria
4*(3^0)+0 = 4
4*(3^1)+1 = 13
4*(3^2)+2 = 38

Similarly 4*(3^3)+3 = 111


QUERY 30

135, 226, 353, … , 739

Himanshu Kathuria
5^3+10 = 135
6^3+10 = 226
7^3+10 = 353

Similarly 8^3+10 = 522
We see 739 is also having the same pattern i.e. 9^3+10


QUERY 31

96, 100, 132

6       4       6
5       7       3
21   32      x

MAHA GUPTA
First row: (21 – 5)*6 = 96
Second row: (32 – 7)*4 = 100
Third Row: (x – 3)*6 = 132; means x = 25


QUERY 32

Jyoti whose house is to the east, comes out of her house and turns east. After walking for 100 mtrs, she turns right and goes 50 mtrs. Then she turns right again. In which direction is she going now?

east
west
north
south

MAHA GUPTA
Jyoti’s house is in the east means the gate of the house opens in the west, means when she turns east after coming out of her house walking 100 meters, her front side was in the east. Means on her right is the south. Now she goes 50 meters to the south and turns right, obviously she is going to the west now. So WEST (option ‘2’) is the right answer.


QUERY 33

If 2463 = 36 and 5552 = 30; then 6732 = ?

32
36
34
39

Mohan Singh
2463 = (2+4+6)*3 = 36
5552 = (5+5+5)*2 = 30
6732 = (6+7+3)*2 = 32 (option ‘1’)


QUERY 34

32 : 21 :: 35 : ?

51
53
32
26

Harvendra Harji
32 = 23-2 = 21
35 = 53-2 = 51 (option ‘1’)


QUERY 35

37, 60, 129, ?, 405, 612

MAHA GUPTA
The difference of
2nd term – 1st term = 60 – 37 = 23 i.e. 23*1
3rd term – 2nd term = 129 – 60 = 69 i.e. 23*3
————————
————————
6th term – 5th term = 612 – 405 = 207 i.e. 23*9

It’s obvious from above that this difference is increasing by 23*consecutive odd numbers

Therefore the difference of 4th term & 3rd term = 23*5 = 115
Hence the 4th term i.e. missing term = 129+115 = 244 (answer)


QUERY 36

786, 786, ?, 753, 690, 566

MAHA GUPTA
The difference of
1st term – 2nd term = 786 – 786 = 0
————————-
————————-
4th term – 5th term = 753 – 690 = 63
5th term – 6th term = 690 – 566 = 124

We can easily observe from the above that the difference between any two terms is increasing in the trend 1^3 -1; 2^3 – 1; 3^3 -1; 4^3 -1; 5^3 -1

Therefore 2nd term – 2^3 – 1
= 786 – 7 = 779 (answer)


QUERY 37

1, 9, 17, 33, 49, 73, ?

97
98
99
101

MAHA GUPTA
2nd and 3rd terms are the result of addition of 8*1 i.e. 8 to their previous ones respectively.

4th and 5th terms are the result of 8*2 i.e.16 to their previous ones respectively.

6th term is the result of 8*3 i.e. 24 to its previous term.
Similarly the 7th term will be 73 + 24 = 97 (option ‘1’)


QUERY 38

10 : 50 :: 12 : ?

94
56
63
84

Ashwani Singh
10*3+20 = 50
12*3+20 = 56 (option ‘2’)


QUERY 39

9 : 80 :: 8 : ?

27
36
49
71

SHIPRA DIXIT
LHS: 9*10 = 90
90 – (9+1) = 80

RHS: 8*10 = 80
80 – (8+1) = 71 (option ‘4’)

MAHA GUPTA
LHS: 9*8 = 72
72 + (9 – 1) =80

RHS: 8*8 = 64
64 + (8 – 1) = 71 (option ‘4’)


QUERY 40

96, 101, 126, 187, ?

MAHIMA SINGH
Difference in 96 and 101 = 5; 5 = 2^2 + 1^2
Difference in 101 and 126 = 25; 25 = 4^2 + 3^3
Difference in 126 and 187 = 61; 61 = 6^2 + 5^2

Obviously now we need a number whose difference with 187 = 8^2+7^2 =113 and is greater than it.

Therefore it is 187+113 = 300 (answer)

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Maha Gupta

Maha Gupta

Founder of www.examscomp.com and guiding aspirants on SSC exam affairs since 2010 when objective pattern of exams was introduced first in SSC. Also the author of the following books:

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