# QUESTIONS ON REASONING (PART-2)

#### QUESTIONS ON REASONING (PART-2)

Most of these questions are taken from the previous examinations conducted by the Staff Selection Commission (SSC) of the General Intelligence and Reasoning section of the following exams as well as other exams. They are all solved and supported by detailed explanation.

1. Combined Graduate Level (CGL) Exam Tier-I

2. Combined Higher Secondary (10+2) Exam (CHSL) Tier-I

3. SI in Delhi Police and CPO Exam Tier-I

4. Stenographers Exam

5. Grade-II DASS Exam conducted by Delhi Staff Subordinate Services (DSSSB)

#### QUERY 21

**13 : 19 :: 21 : ?**

41

141

81

14

**MAHA GUPTA**

Relation between the first two terms:

1^2 & 3^2 = 19

Likewise 2^2 & 1^2 = 41 (option ‘1’)

QUERY 22

**DKM, FJP, HIS, JHV, ….**

LGY

HGY

IGZ

IGY

**SANGEETA RATHEE**

1st = 4 11 13

2nd = 6 10 16

3rd = 8 9 19

4th = 10 8 22

So the 5th = 12 7 25 = LGY (option ‘1’)

QUERY 23

**85+25 = 50, 97+65 = 93, 72+94 = ?**

92

50

67

60

**SHIV KISHOR**

1st = 8*5 + 2*5 = 50

2nd = 9*7 + 6*5 = 93

Therefore 3rd = 7*2 + 9*4 = 50

QUERY 24

**11, 29, 55, …. , 131**

110

81

89

78

**Dibyendu Dutta**

Ist: 3^2 + 2 = 11

IInd: 5^2 + 4 = 29

IIIrd: 7^2 + 6 = 55

So IVth: 9^2 + 8 = 89 (option ‘3’)

**Sangeeta Rathee**

89 (option ‘3’)

every time the difference increases by 8

QUERY 25

**If ‘CARING’ is coded as ‘EDVGKC’, and ‘SHARES’ is coded as ‘UKEPBO’, how will CASKET be coded as in the same code?**

EDXIBP

EDWIAP

EDWPAI

EDWIBP

**Sangeeta Rathee**

The difference is such as:

+2+3+4 -2-3-4

Therefore EDWIAP (option ‘2’) is correct.

QUERY 26

**12, 32, 56, 1130, ?**

15640

19760

41330

52840

**Pankaj Kumar**

1+2 = 3 & 1*2 = 2, so 32

3+2 = 5 & 3*2 = 6, so 56

5+6 = 11 & 5*6 = 30, so 1130

11+30 = 41 & 11*30 = 330, so, 41330

QUERY 27

**If 55+66 = 33, 22+99 = 33, then 44+88 = ?**

33

36

38

40

**AMIT KUMAR**

(5+6)*3 = 33

(2+9)*3 = 33

Therefore (4+8)*3 = 36

#### QUERY 28

**If 62 x 3 = 30, 52 x 5 = 35, 32 x 6 = 24; then 84 x 3 = ?**

**MAHA GUPTA**

6*(2+3) = 30

5*(2+5) = 35

3*(2+6) = 24

Therefore 8*(4+3) = 56

QUERY 29

**4, 13, 38, ?**

123

58

96

111

**Himanshu Kathuria**

4*(3^0)+0 = 4

4*(3^1)+1 = 13

4*(3^2)+2 = 38

Similarly 4*(3^3)+3 = 111

QUERY 30

**135, 226, 353, … , 739**

**Himanshu Kathuria**

5^3+10 = 135

6^3+10 = 226

7^3+10 = 353

Similarly 8^3+10 = 522

We see 739 is also having the same pattern i.e. 9^3+10

QUERY 31

**96, 100, 132**

6 4 6

5 7 3

21 32 x

**MAHA GUPTA**

First row: (21 – 5)*6 = 96

Second row: (32 – 7)*4 = 100

Third Row: (x – 3)*6 = 132; means x = 25

QUERY 32

**Jyoti whose house is to the east, comes out of her house and turns east. After walking for 100 mtrs, she turns right and goes 50 mtrs. Then she turns right again. In which direction is she going now?**

east

west

north

south

** MAHA GUPTA**

Jyoti’s house is in the east means the gate of the house opens in the west, means when she turns east after coming out of her house walking 100 meters, her front side was in the east. Means on her right is the south. Now she goes 50 meters to the south and turns right, obviously she is going to the west now. So WEST (option ‘2’) is the right answer.

QUERY 33

**If 2463 = 36 and 5552 = 30; then 6732 = ?**

32

36

34

39

**Mohan Singh**

2463 = (2+4+6)*3 = 36

5552 = (5+5+5)*2 = 30

6732 = (6+7+3)*2 = 32 (option ‘1’)

QUERY 34

**32 : 21 :: 35 : ?**

51

53

32

26

**Harvendra Harji**

32 = 23-2 = 21

35 = 53-2 = 51 (option ‘1’)

QUERY 35

**37, 60, 129, ?, 405, 612**

**MAHA GUPTA**

The difference of

2nd term – 1st term = 60 – 37 = 23 i.e. 23*1

3rd term – 2nd term = 129 – 60 = 69 i.e. 23*3

————————

————————

6th term – 5th term = 612 – 405 = 207 i.e. 23*9

It’s obvious from above that this difference is increasing by 23*consecutive odd numbers

Therefore the difference of 4th term & 3rd term = 23*5 = 115

Hence the 4th term i.e. missing term = 129+115 = 244 (answer)

QUERY 36

**786, 786, ?, 753, 690, 566**

**MAHA GUPTA**

The difference of

1st term – 2nd term = 786 – 786 = 0

————————-

————————-

4th term – 5th term = 753 – 690 = 63

5th term – 6th term = 690 – 566 = 124

We can easily observe from the above that the difference between any two terms is increasing in the trend 1^3 -1; 2^3 – 1; 3^3 -1; 4^3 -1; 5^3 -1

Therefore 2nd term – 2^3 – 1

= 786 – 7 = 779 (answer)

QUERY 37

**1, 9, 17, 33, 49, 73, ?**

97

98

99

101

**MAHA GUPTA**

2nd and 3rd terms are the result of addition of 8*1 i.e. 8 to their previous ones respectively.

4th and 5th terms are the result of 8*2 i.e.16 to their previous ones respectively.

6th term is the result of 8*3 i.e. 24 to its previous term.

Similarly the 7th term will be 73 + 24 = 97 (option ‘1’)

QUERY 38

**10 : 50 :: 12 : ?**

94

56

63

84

**Ashwani Singh**

10*3+20 = 50

12*3+20 = 56 (option ‘2’)

QUERY 39

**9 : 80 :: 8 : ?**

27

36

49

71

**SHIPRA DIXIT**

LHS: 9*10 = 90

90 – (9+1) = 80

RHS: 8*10 = 80

80 – (8+1) = 71 (option ‘4’)

**MAHA GUPTA**

LHS: 9*8 = 72

72 + (9 – 1) =80

RHS: 8*8 = 64

64 + (8 – 1) = 71 (option ‘4’)

QUERY 40

**96, 101, 126, 187, ?**

**MAHIMA SINGH**

Difference in 96 and 101 = 5; 5 = 2^2 + 1^2

Difference in 101 and 126 = 25; 25 = 4^2 + 3^3

Difference in 126 and 187 = 61; 61 = 6^2 + 5^2

Obviously now we need a number whose difference with 187 = 8^2+7^2 =113 and is greater than it.

Therefore it is 187+113 = 300 (answer)