REASONING

# QUESTIONS ON REASONING (PART-3)

#### QUESTIONS ON REASONING (PART-3)

QUERY 41

532+781 = 21, 862+910 = 21, 796+355 = ?

21
30
31
32

MANOJ SHARMA
(5+3+2) + (7+8+1) – 5 = 21
(8+6+2) + (9+1+0) – 5 = 21
(7+9+6) + (3+5+5) – 5 = 30 (option ‘2’)

#### QUERY 42

Select the one which is different from the others:
51-90
41-70
31-60
21-30

31-60 (option ‘3’). Subtract the second from double of the first one; you’ll find the difference of 12 but in option ‘3’ it’s different i.e. 2.

#### QUERY 43

2(5)6 = 10; 5(4)3 = 14; 9(8)2 = ?

28
11
13
15

SHIV KISHOR
LHS: 2(5)6
= (2×6 – 5) + 3
= 10 (RHS)

LHS: 5(4)3
= (5×3 – 4) + 3
= 14 (RHS)

LHS: 9(8)2
= (9×2 – 8) + 3
= 13 (RHS)

#### QUERY 44

If 8×4=36; 7×5=48; 3×9=36; then 8×7=?

90
84
48
72

MAHA GUPTA
(1+8)*4=36
(1+7)*(5+1)=48
(1+3)*9=36
(1+8)*(1+7)=72 (option ‘4’)

EXPLANATION: Alternatively add 1 to the first term and multiply it by the next term.

Then alternatively Add 1 to the first and second term both; and multiply them.

#### QUERY 45

0, 4, 18, 48, ? , 180

MAHA GUPTA
(1^2)*0 = 0
(2^2)*1 = 4
(3^2)*2 = 18
(4^2)*3 = 48
(6^2)*5 = 180

#### QUERY 46

1, 2, 5, 10, 20, 50, 100, ?

MAHA GUPTA
In each block of three numbers, the second number is twice of its predecessor and the third number is 2.5 times of its predecessor. See how:
Block-I: 1, 2, 5
2 = Twice of 1
5 = 2.5 of 2

Block-II: 10, 20, 50
20 = Twice of 10
50 = 2.5 of 20

Block=III
100, ?; —

Therefore the number will be twice of 100 i.e. 200 (answer)

#### QUERY 47 MAHA GUPTA

Add all the numbers of each row and divide it by 2; the required number is 6 (answer)

#### QUERY 48 AVDHESH SINGH

(4×6)/3=8
(2×8)/4=4
(6×5)/3=10

Therefore, answer is 3

#### QUERY 49

If 1 = 2
2 = 12
3 = 36
Then 5 = ?

DEEPAK SHARMA
The pattern is number^2*(number+1); see how

(1^2)*(1+1) = 2
(2^2)*(2+1) = 12
(3^2)*(3+1) = 36

Therefore, (5^2)*(5+1) = 150 (answer)

#### QUERY 50

2+3 = 8
3+7 = 27
4+5 = 32
5+8 = 60
6+7 = 72
7+8 = ?

MAHA GUPTA
2*3 + 2*1 = 8
3*7 + 3*2 = 27
4*5 + 4*3 = 32
5*8 + 5*4 = 60
6*7 + 6*5 = 72

Therefore, 7*8 + 7*6 = 98 (answer)

#### QUERY 51

0, 6, 24, 60, ?, 210

117
119
153
120

NARVEER RAO
Start cubing from 1, 2, 3 and like that and subtract from it the number itself; see how
1^3 – 1 = 0
2^3 – 2 = 6
3^3 – 3 = 24
4^3 – 4 = 60

Therefore the next number is 5^3 – 5 = 120 (option ‘4’)

Let’s check it on the next number
6^3 – 6 = 210

#### QUERY 52 MANOJ KAUSHIK

19 -10 = 9
7 – 6 = 1
6 – 2 = 4
Now the pattern is quite understable

Therefore 9 – ? = 6
==> ? = 3 (answer)

#### QUERY 53

12 : 90 : : 16 : ?

108
112
120
256

MAHA GUPTA
12*7 + 12/2 = 90
16*7 + 16/2 = 120 (option ‘3’)

#### QUERY 54

3, 8, 6, 14, ?, 20

11
10
9
8

MAHA GUPTA
The first number 3 is increasing by 3 alternatively; and the second number 8 is increasing by 6 alternatively.

Therefore 9 (option ‘3’) is the answer.

#### QUERY 55

1/4, 1/4, 1/2, 3/2, 6, ?

10
15
30
40

MAHA GUPTA
Every number is multiplied by a consecutive natural number beginning from 1, to get the next number; see how
(1/4)*1 = 1/4
(1/4)*2 = 1/2
(1/2)*3 = 3/2
(3/2)*4 = 6

Therefore the desired number = 6*5 = 30 (option ‘3’)

#### QUERY 56

AGRA -60, GOA -24, DELHI -120, CHENNAI – ?

120
124
336
350

MAHA GUPTA
GOA——3 letter word——3*8 = 24
AGRA——4 letter word——4*15 = 60
DELHI——5 letter word——5*24 = 120

It shows that multiplicands of 3, 4, 5 are increasing in the order of 7, 9 and so on

Means if the city name is having 6 letters its value will be 6*(24+11) = 6*35 = 210

We see CHENNAI is a 7 letter word; therefore its value = 7*(35+13) = 7*48 = 336 (option ‘3’)

#### QUERY 57

3, 6, 5, 20, 7, 42, 9, ?

MAHA GUPTA
Consider every set of two numbers from the beginning
3*2 = 6
5*4 = 20
7*6 = 42

Therefore the required number
9*8 = 72 (answer)

#### QUERY 58

3, 6, 8, 16, 18, ?

MAHA GUPTA
Numbers at even places are double of their previous one
So the required number = 18*2 = 36

#### QUERY 59

68 : 130 :: ? : 350

210
222
240
282

YOGESH GOEL
4^3 + 4 = 68
5^3 + 5 = 130
6^3 + 6 = 222 (option ‘2’)
7^3 + 7 = 350

#### QUERY 60

Find out the wrong number from the given sequence:
5, 27, 61, 122, 213, 340, 509

27
61
122
509

MAHA GUPTA
5 = 2^3 – 3
——
61 = 4^3 – 3
122 = 5^3 – 3
213 = 6^3 – 3
340 = 7^3 – 3
509 = 8^3 – 3

Therefore the desired number = 3^3 – 3 = 24

Hence 27 (option ‘1’) is wrong in the series

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