REASONING

# QUESTIONS ON REASONING (PART-3)

#### QUESTIONS ON REASONING (PART-3)

Most of these questions are taken from the previous examinations conducted by the Staff Selection Commission (SSC) of the General Intelligence and Reasoning section of the following exams as well as other exams. They are all solved and supported by detailed explanation.

1. Combined Graduate Level (CGL) Exam Tier-I

2. Combined Higher Secondary (10+2) Exam (CHSL) Tier-I

3. SI in Delhi Police and CPO Exam Tier-I

4. Stenographers Exam

5. Grade-II DASS Exam conducted by Delhi Staff Subordinate Services (DSSSB)

QUERY 41

532+781 = 21, 862+910 = 21, 796+355 = ?

21
30
31
32

MANOJ SHARMA
(5+3+2) + (7+8+1) – 5 = 21
(8+6+2) + (9+1+0) – 5 = 21
(7+9+6) + (3+5+5) – 5 = 30 (option ‘2’)

#### QUERY 42

Select the one which is different from the others:
51-90
41-70
31-60
21-30

31-60 (option ‘3’). Subtract the second from double of the first one; you’ll find the difference of 12 but in option ‘3’ it’s different i.e. 2.

#### QUERY 43

2(5)6 = 10; 5(4)3 = 14; 9(8)2 = ?

28
11
13
15

SHIV KISHOR
LHS: 2(5)6
= (2×6 – 5) + 3
= 10 (RHS)

LHS: 5(4)3
= (5×3 – 4) + 3
= 14 (RHS)

LHS: 9(8)2
= (9×2 – 8) + 3
= 13 (RHS)

#### QUERY 44

If 8×4=36; 7×5=48; 3×9=36; then 8×7=?

90
84
48
72

MAHA GUPTA
(1+8)*4=36
(1+7)*(5+1)=48
(1+3)*9=36
(1+8)*(1+7)=72 (option ‘4’)

EXPLANATION: Alternatively add 1 to the first term and multiply it by the next term.

Then alternatively Add 1 to the first and second term both; and multiply them.

#### QUERY 45

0, 4, 18, 48, ? , 180

MAHA GUPTA
(1^2)*0 = 0
(2^2)*1 = 4
(3^2)*2 = 18
(4^2)*3 = 48
(6^2)*5 = 180

#### QUERY 46

1, 2, 5, 10, 20, 50, 100, ?

MAHA GUPTA
In each block of three numbers, the second number is twice of its predecessor and the third number is 2.5 times of its predecessor. See how:
Block-I: 1, 2, 5
2 = Twice of 1
5 = 2.5 of 2

Block-II: 10, 20, 50
20 = Twice of 10
50 = 2.5 of 20

Block=III
100, ?; —

Therefore the number will be twice of 100 i.e. 200 (answer)

#### QUERY 47 MAHA GUPTA

Add all the numbers of each row and divide it by 2; the required number is 6 (answer)

#### QUERY 48 AVDHESH SINGH

(4×6)/3=8
(2×8)/4=4
(6×5)/3=10

#### QUERY 49

If 1 = 2
2 = 12
3 = 36
Then 5 = ?

DEEPAK SHARMA
The pattern is number^2*(number+1); see how

(1^2)*(1+1) = 2
(2^2)*(2+1) = 12
(3^2)*(3+1) = 36

#### QUERY 50

2+3 = 8
3+7 = 27
4+5 = 32
5+8 = 60
6+7 = 72
7+8 = ?

MAHA GUPTA
2*3 + 2*1 = 8
3*7 + 3*2 = 27
4*5 + 4*3 = 32
5*8 + 5*4 = 60
6*7 + 6*5 = 72

Therefore, 7*8 + 7*6 = 98 (answer)

#### QUERY 51

0, 6, 24, 60, ?, 210

117
119
153
120

NARVEER RAO
Start cubing from 1, 2, 3 and like that and subtract from it the number itself; see how
1^3 – 1 = 0
2^3 – 2 = 6
3^3 – 3 = 24
4^3 – 4 = 60

Therefore the next number is 5^3 – 5 = 120 (option ‘4’)

Let’s check it on the next number
6^3 – 6 = 210

#### QUERY 52 MANOJ KAUSHIK

19 -10 = 9
7 – 6 = 1
6 – 2 = 4
Now the pattern is quite understable

Therefore 9 – ? = 6

#### QUERY 53

12 : 90 : : 16 : ?

108
112
120
256

MAHA GUPTA
12*7 + 12/2 = 90
16*7 + 16/2 = 120 (option ‘3’)

#### QUERY 54

3, 8, 6, 14, ?, 20

11
10
9
8

MAHA GUPTA
The first number 3 is increasing by 3 alternatively; and the second number 8 is increasing by 6 alternatively.

Therefore 9 (option ‘3’) is the answer.

#### QUERY 55

1/4, 1/4, 1/2, 3/2, 6, ?

10
15
30
40

MAHA GUPTA
Every number is multiplied by a consecutive natural number beginning from 1, to get the next number; see how
(1/4)*1 = 1/4
(1/4)*2 = 1/2
(1/2)*3 = 3/2
(3/2)*4 = 6

Therefore the desired number = 6*5 = 30 (option ‘3’)

#### QUERY 56

AGRA -60, GOA -24, DELHI -120, CHENNAI – ?

120
124
336
350

MAHA GUPTA
GOA——3 letter word——3*8 = 24
AGRA——4 letter word——4*15 = 60
DELHI——5 letter word——5*24 = 120

It shows that multiplicands of 3, 4, 5 are increasing in the order of 7, 9 and so on

Means if the city name is having 6 letters its value will be 6*(24+11) = 6*35 = 210

We see CHENNAI is a 7 letter word; therefore its value = 7*(35+13) = 7*48 = 336 (option ‘3’)

#### QUERY 57

3, 6, 5, 20, 7, 42, 9, ?

MAHA GUPTA
Consider every set of two numbers from the beginning
3*2 = 6
5*4 = 20
7*6 = 42

Therefore the required number

#### QUERY 58

3, 6, 8, 16, 18, ?

MAHA GUPTA
Numbers at even places are double of their previous one
So the required number = 18*2 = 36

#### QUERY 59

68 : 130 :: ? : 350

210
222
240
282

YOGESH GOEL
4^3 + 4 = 68
5^3 + 5 = 130
6^3 + 6 = 222 (option ‘2’)
7^3 + 7 = 350

#### QUERY 60

Find out the wrong number from the given sequence:
5, 27, 61, 122, 213, 340, 509

27
61
122
509

MAHA GUPTA
5 = 2^3 – 3
——
61 = 4^3 – 3
122 = 5^3 – 3
213 = 6^3 – 3
340 = 7^3 – 3
509 = 8^3 – 3

Therefore the desired number = 3^3 – 3 = 24

Hence 27 (option ‘1’) is wrong in the series

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