# QUESTIONS ON REASONING (PART-3)

#### QUESTIONS ON REASONING (PART-3)

Most of these questions are taken from the previous examinations conducted by the Staff Selection Commission (SSC) of the General Intelligence and Reasoning section of the following exams as well as other exams. They are all solved and supported by detailed explanation.

1. Combined Graduate Level (CGL) Exam Tier-I

2. Combined Higher Secondary (10+2) Exam (CHSL) Tier-I

3. SI in Delhi Police and CPO Exam Tier-I

4. Stenographers Exam

5. Grade-II DASS Exam conducted by Delhi Staff Subordinate Services (DSSSB)

**QUERY 41**

**532+781 = 21, 862+910 = 21, 796+355 = ?**

21

30

31

32

**MANOJ SHARMA**

(5+3+2) + (7+8+1) – 5 = 21

(8+6+2) + (9+1+0) – 5 = 21

(7+9+6) + (3+5+5) – 5 = 30 (option ‘2’)

QUERY 42

**Select the one which is different from the others:**

** 51-90**

** 41-70**

** 31-60**

** 21-30**

**RAKESH YADAV**

31-60 (option ‘3’). Subtract the second from double of the first one; you’ll find the difference of 12 but in option ‘3’ it’s different i.e. 2.

QUERY 43

**2(5)6 = 10; 5(4)3 = 14; 9(8)2 = ?**

28

11

13

15

**SHIV KISHOR**

LHS: 2(5)6

= (2×6 – 5) + 3

= 10 (RHS)

LHS: 5(4)3

= (5×3 – 4) + 3

= 14 (RHS)

LHS: 9(8)2

= (9×2 – 8) + 3

= 13 (RHS)

QUERY 44

If 8×4=36; 7×5=48; 3×9=36; then 8×7=?

90

84

48

72

**MAHA GUPTA**

(1+8)*4=36

(1+7)*(5+1)=48

(1+3)*9=36

(1+8)*(1+7)=72 (option ‘4’)

EXPLANATION: Alternatively add 1 to the first term and multiply it by the next term.

Then alternatively Add 1 to the first and second term both; and multiply them.

QUERY 45

**0, 4, 18, 48, ? , 180**

**MAHA GUPTA**

(1^2)*0 = 0

(2^2)*1 = 4

(3^2)*2 = 18

(4^2)*3 = 48

(5^2)*4= 100 (answer)

(6^2)*5 = 180

QUERY 46

**1, 2, 5, 10, 20, 50, 100, ?**

**MAHA GUPTA**

In each block of three numbers, the second number is twice of its predecessor and the third number is 2.5 times of its predecessor. See how:

Block-I: 1, 2, 5

2 = Twice of 1

5 = 2.5 of 2

Block-II: 10, 20, 50

20 = Twice of 10

50 = 2.5 of 20

Block=III

100, ?; —

Therefore the number will be twice of 100 i.e. 200 (answer)

QUERY 47

**MAHA GUPTA**

Add all the numbers of each row and divide it by 2; the required number is 6 (answer)

QUERY 48

**AVDHESH SINGH**

(4×6)/3=8

(2×8)/4=4

(6×5)/3=10

Therefore, answer is 3

QUERY 49

**If 1 = 2**

** 2 = 12**

** 3 = 36**

** Then 5 = ?**

**DEEPAK SHARMA
**The pattern is number^2*(number+1); see how

(1^2)*(1+1) = 2

(2^2)*(2+1) = 12

(3^2)*(3+1) = 36

Therefore, (5^2)*(5+1) = 150 (answer)

QUERY 50

**2+3 = 8**

** 3+7 = 27**

** 4+5 = 32**

** 5+8 = 60**

** 6+7 = 72**

** 7+8 = ?**

**MAHA GUPTA**

2*3 + 2*1 = 8

3*7 + 3*2 = 27

4*5 + 4*3 = 32

5*8 + 5*4 = 60

6*7 + 6*5 = 72

Therefore, 7*8 + 7*6 = 98 (answer)

QUERY 51

**0, 6, 24, 60, ?, 210**

117

119

153

120

**NARVEER RAO**

Start cubing from 1, 2, 3 and like that and subtract from it the number itself; see how

1^3 – 1 = 0

2^3 – 2 = 6

3^3 – 3 = 24

4^3 – 4 = 60

Therefore the next number is 5^3 – 5 = 120 (option ‘4’)

Let’s check it on the next number

6^3 – 6 = 210

QUERY 52

**MANOJ KAUSHIK**

19 -10 = 9

7 – 6 = 1

6 – 2 = 4

Now the pattern is quite understable

Therefore 9 – ? = 6

==> ? = 3 (answer)

QUERY 53

**12 : 90 : : 16 : ?**

108

112

120

256

**MAHA GUPTA**

12*7 + 12/2 = 90

16*7 + 16/2 = 120 (option ‘3’)

QUERY 54

**3, 8, 6, 14, ?, 20**

11

10

9

8

**MAHA GUPTA**

The first number 3 is increasing by 3 alternatively; and the second number 8 is increasing by 6 alternatively.

Therefore 9 (option ‘3’) is the answer.

QUERY 55

**1/4, 1/4, 1/2, 3/2, 6, ?**

10

15

30

40

**MAHA GUPTA**

Every number is multiplied by a consecutive natural number beginning from 1, to get the next number; see how

(1/4)*1 = 1/4

(1/4)*2 = 1/2

(1/2)*3 = 3/2

(3/2)*4 = 6

Therefore the desired number = 6*5 = 30 (option ‘3’)

QUERY 56

**AGRA -60, GOA -24, DELHI -120, CHENNAI – ?**

120

124

336

350

**MAHA GUPTA**

GOA——3 letter word——3*8 = 24

AGRA——4 letter word——4*15 = 60

DELHI——5 letter word——5*24 = 120

It shows that multiplicands of 3, 4, 5 are increasing in the order of 7, 9 and so on

Means if the city name is having 6 letters its value will be 6*(24+11) = 6*35 = 210

We see CHENNAI is a 7 letter word; therefore its value = 7*(35+13) = 7*48 = 336 (option ‘3’)

QUERY 57

**3, 6, 5, 20, 7, 42, 9, ?**

**MAHA GUPTA**

Consider every set of two numbers from the beginning

3*2 = 6

5*4 = 20

7*6 = 42

Therefore the required number

9*8 = 72 (answer)

QUERY 58

**3, 6, 8, 16, 18, ?**

**MAHA GUPTA**

Numbers at even places are double of their previous one

So the required number = 18*2 = 36

#### QUERY 59

**68 : 130 :: ? : 350**

210

222

240

282

**YOGESH GOEL**

4^3 + 4 = 68

5^3 + 5 = 130

6^3 + 6 = 222 (option ‘2’)

7^3 + 7 = 350

QUERY 60

**Find out the wrong number from the given sequence:**

** 5, 27, 61, 122, 213, 340, 509**

27

61

122

509

**MAHA GUPTA**

5 = 2^3 – 3

——

61 = 4^3 – 3

122 = 5^3 – 3

213 = 6^3 – 3

340 = 7^3 – 3

509 = 8^3 – 3

Therefore the desired number = 3^3 – 3 = 24

Hence 27 (option ‘1’) is wrong in the series