REASONING

QUESTIONS ON REASONING (PART-4)

QUESTIONS ON REASONING (PART-4)

Most of these questions are taken from the previous examinations conducted by the Staff Selection Commission (SSC) of the General Intelligence and Reasoning section of the following exams as well as other exams. They are all solved and supported by detailed explanation.

1. Combined Graduate Level (CGL) Exam Tier-I

2. Combined Higher Secondary (10+2) Exam (CHSL) Tier-I

3. SI in Delhi Police and CPO Exam Tier-I

4. Stenographers Exam

5. Grade-II DASS Exam conducted by Delhi Staff Subordinate Services (DSSSB)

QUERY 61

If RED = 6720; then GREEN = ?

1677209
1677199
16771209
9207716

MAHA GUPTA
RED = DER = 4/5/18; on adding 2 to each = 6/7/20 = 6720

GREEN = NEERG = 14/5/5/18/7; adding 2 to each =16/7/7/20/9 = 1677209 (option ‘1’)


QUERY 62

1, 3, 5, 1, 9, -3, 13, ?

MAHA GUPTA
The given sequence can be bifurcated in two sequences; one sequence of numbers at odd places and the other sequence of numbers at even places; see how

Sequence of numbers at odd places:
1, 5, 9, 13
Every next number is more by 4 than its previous

Sequence of numbers at even places:
3, 1, -3, ?
We see here that every next number is decreasing by consecutive multiple of 2.

Hence the required number = -3 – 6 = -9 (answer)


QUERY 63

3917, 3526, ? , 2857

3389
2682
3082
3174

Chaudhary Deepak Singh
Subtract number comprising first 3 digits from the number itself to get the next number
3917 – 391 = 3526
3526 – 352 = 3174 (option ‘4’)

Let’s check it for the next number
3174 – 317 = 2857


QUERY 64

61, 52, 63, 94, 46, ?

19
18
17
none

MAHA GUPTA
If seen closely every number is reverse of a square of a consecutive natural starting from 4; see how
4^2 = 16; reverse of this is 61
5^2 = 25; reverse of this is 52
6^2 = 36; reverse of this is 63
7^2 = 49; reverse of this is 94
8^2 = 64; reverse of this is 46

Therefore the required number
Reverse of 9^2 = 81 i.e, 18 (option ‘2’)


QUERY 65

1944, 108, ?, 6, 3

MAHA GUPTA
1944/108 = 18
108/18=6
18/6=3

So the required number is 18


QUERY 66

2, 5, 10, 19, 36, ?

MAHA GUPTA
2^1 + 0 = 2
2^2 + 1 = 5
2^3 + 2 = 10
2^4 + 3 = 19
2^5 + 4 = 36

Therefore the next number is
2^6 + 5 = 69


QUERY 67

54 + 43 = 2, 60 + 51 = 10; then 62 + 72 = ?

30
18
20
09

Shubham Gurjar
54 + 43 = 97; 9 – 7 = 2
60 + 51 = 111; 11 – 1 = 10
Therefore, 62 + 72 = 134; 13 – 4 = 9 (option ‘4’)


QUERY 68

54 : 41 :: 36 : ?

55
45
60
35

Kumar Saurabh
5^2 + 4^2 = 41
So, 3^2 + 6^2 = 45 (option ‘2’)


QUERY 69

If 25 + 25 = 600
35 + 35 = 1190:
then
45 + 45 = ?

MAHA GUPTA
25*25 – 25 = 600
35*35 – 35 = 1190

Therefore the required number is 45*45 – 45 = 1980


QUERY 70

80 : 730 :: ? : 344

70
40
48
52

KIRAN MALIK
80 = 9*9 -1
730 = 9*9*9 + 1

? = 7*7 – 1 = 48 (option ‘3’)
344 = 7*7*7 + 1


QUERY 71

1, 2, 8, 33, 148, ?

265
565
465
765

SHIV KISHOR
1*0 + 1^2 = 1
1*1 + 1^2 = 2
2*2 + 2^2 = 8
8*3 + 3^2 = 33
33*4 + 4^2 = 148
148*5 + 5^2 = 765 (option ‘4’)


QUERY 72

If 136×150=60, 357×510=90; then 931×114=?

78
76
72
84

Amit Rohilla
(1+3+6)*(1+5+0) = 60
(3+5+7)*(5+1+0) = 90

Therefore, (9+3+1)*(1+1+4) = 78 (option ‘1’)


QUERY 73

13 12 5

17 15 8

25 24 ?

29 21 20

9
11
15
7

MAHA GUPTA
13^2 – 12^2 = 5^2 —- 5
17^2 – 15^2 = 8^2 —- 8
25^2 – 24^2 = 7^2 —- 7 (option ‘4’)
29^2 – 21^2 = 20^2 —- 20


QUERY 74

Paper : Pencil :: Cup : ?

Drink
Saucer
China Clay
Tea

MAHA GUPTA
SAUCER (option ‘2’). The relation between PAPER and PENCIL is that both are items of stationery; likewise the relation between CUP and SAUCER is that both are items of pottery. DRINK is not possible as CUP is a means of drinking of something. CHINA CLAY is not possible as a cup may be made of it. TEA again is not possible as its a content that a cup may have inside.


QUERY 75

3     8     10     2     ?     1
6    56   90     2   20    0

0
3
5
7

MAHA GUPTA
Multiply the number in the first row with its predecessor to get the number in the second row; see how:
3*2 = 6
8*7 = 56
10*9 = 90
2*1 = 2
5*4 = 20
1*0 = 0

Therefore 5 (option ‘3’) is the answer

OR; Square the number in the first row and subtract the number itself from it to get the number in the second row; see how:
3^2 – 3 = 6
8^2 – 8 = 56
10^2 – 10 = 90
2^2 – 2 = 2
5^2 – 5 = 20
1^2 – 1 = 0

Therefore 5 (option ‘3’) is the answer.


QUERY 76

1901810_593419760750196_1665410217_n

An Ssc Aspirant

1^3 – 1 = 0
2^3 – 3 = 5
3^3 – 5 = 22
4^3 – 7 = 57 (option ‘B’)


QUERY 77

3       4       6
5       7       3
1       2       7
35  69       ?

82
94
84
42

MAHA GUPTA
Add the squares of all the numbers of the first three rows to get the number in the last row; see how

3^2 + 5^2 + 1^2 = 35
4^2 + 7^2 + 2^2 = 69

Therefore 6^2 + 3^2 + 7^2 = 94 (option ‘2’)


QUERY 78

130 : 154 :: 178 : ?

24
180
204
206

MAHA GUPTA
(11^2) + 9 = 130
(12^2) +10 = 154

Like above
(13^2) + 9 = 178
(14^2) +10 = 206 (option ‘4’)


QUERY 79

Find odd one out
1, 5, 9, 15, 25, 37, 49

MAHA GUPTA
15 as it should be 17; The pattern of difference between numbers is :
4, 4
8, 8
12, 12


QUERY 80

Find odd one out
445, 221, 109, 46, 25, 11, 4

Parvender Singh Yadav
Replace 46 by 53; see how
4 + 7*1 = 11
11 + 7*2 = 25
25 + 7*4 = 53 (desired number)
53 + 7*8 = 109
109 + 7*16 = 221
221 + 7*32 = 445

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Maha Gupta

Maha Gupta

Founder of www.examscomp.com and guiding aspirants on SSC exam affairs since 2010 when objective pattern of exams was introduced first in SSC. Also the author of the following books:

1. Maha English Grammar (for Competitive Exams)
2. Maha English Practice Sets (for Competitive Exams)