REASONING

# QUESTIONS ON REASONING (PART-4)

#### QUERY 61

If RED = 6720; then GREEN = ?

1677209
1677199
16771209
9207716

MAHA GUPTA
RED = DER = 4/5/18; on adding 2 to each = 6/7/20 = 6720

GREEN = NEERG = 14/5/5/18/7; adding 2 to each =16/7/7/20/9 = 1677209 (option ‘1’)

#### QUERY 62

1, 3, 5, 1, 9, -3, 13, ?

MAHA GUPTA
The given sequence can be bifurcated in two sequences; one sequence of numbers at odd places and the other sequence of numbers at even places; see how

Sequence of numbers at odd places:
1, 5, 9, 13
Every next number is more by 4 than its previous

Sequence of numbers at even places:
3, 1, -3, ?
We see here that every next number is decreasing by consecutive multiple of 2.

Hence the required number = -3 – 6 = -9 (answer)

#### QUERY 63

3917, 3526, ? , 2857

3389
2682
3082
3174

Chaudhary Deepak Singh
Subtract number comprising first 3 digits from the number itself to get the next number
3917 – 391 = 3526
3526 – 352 = 3174 (option ‘4’)

Let’s check it for the next number
3174 – 317 = 2857

#### QUERY 64

61, 52, 63, 94, 46, ?

19
18
17
none

MAHA GUPTA
If seen closely every number is reverse of a square of a consecutive natural starting from 4; see how
4^2 = 16; reverse of this is 61
5^2 = 25; reverse of this is 52
6^2 = 36; reverse of this is 63
7^2 = 49; reverse of this is 94
8^2 = 64; reverse of this is 46

Therefore the required number
Reverse of 9^2 = 81 i.e, 18 (option ‘2’)

#### QUERY 65

1944, 108, ?, 6, 3

MAHA GUPTA
1944/108 = 18
108/18=6
18/6=3

So the required number is 18

#### QUERY 66

2, 5, 10, 19, 36, ?

MAHA GUPTA
2^1 + 0 = 2
2^2 + 1 = 5
2^3 + 2 = 10
2^4 + 3 = 19
2^5 + 4 = 36

Therefore the next number is
2^6 + 5 = 69

#### QUERY 67

54 + 43 = 2, 60 + 51 = 10; then 62 + 72 = ?

30
18
20
09

Shubham Gurjar
54 + 43 = 97; 9 – 7 = 2
60 + 51 = 111; 11 – 1 = 10
Therefore, 62 + 72 = 134; 13 – 4 = 9 (option ‘4’)

#### QUERY 68

54 : 41 :: 36 : ?

55
45
60
35

Kumar Saurabh
5^2 + 4^2 = 41
So, 3^2 + 6^2 = 45 (option ‘2’)

#### QUERY 69

If 25 + 25 = 600
35 + 35 = 1190:
then
45 + 45 = ?

MAHA GUPTA
25*25 – 25 = 600
35*35 – 35 = 1190

Therefore the required number is 45*45 – 45 = 1980

#### QUERY 70

80 : 730 :: ? : 344

70
40
48
52

KIRAN MALIK
80 = 9*9 -1
730 = 9*9*9 + 1

? = 7*7 – 1 = 48 (option ‘3’)
344 = 7*7*7 + 1

#### QUERY 71

1, 2, 8, 33, 148, ?

265
565
465
765

SHIV KISHOR
1*0 + 1^2 = 1
1*1 + 1^2 = 2
2*2 + 2^2 = 8
8*3 + 3^2 = 33
33*4 + 4^2 = 148
148*5 + 5^2 = 765 (option ‘4’)

#### QUERY 72

If 136×150=60, 357×510=90; then 931×114=?

78
76
72
84

Amit Rohilla
(1+3+6)*(1+5+0) = 60
(3+5+7)*(5+1+0) = 90

Therefore, (9+3+1)*(1+1+4) = 78 (option ‘1’)

#### QUERY 73

13 12 5

17 15 8

25 24 ?

29 21 20

9
11
15
7

MAHA GUPTA
13^2 – 12^2 = 5^2 —- 5
17^2 – 15^2 = 8^2 —- 8
25^2 – 24^2 = 7^2 —- 7 (option ‘4’)
29^2 – 21^2 = 20^2 —- 20

#### QUERY 74

Paper : Pencil :: Cup : ?

Drink
Saucer
China Clay
Tea

MAHA GUPTA
SAUCER (option ‘2’). The relation between PAPER and PENCIL is that both are items of stationery; likewise the relation between CUP and SAUCER is that both are items of pottery. DRINK is not possible as CUP is a means of drinking of something. CHINA CLAY is not possible as a cup may be made of it. TEA again is not possible as it’s a content that a cup may have inside.

#### QUERY 75

3     8     10     2     ?     1
6    56   90     2   20    0

0
3
5
7

MAHA GUPTA
Multiply the number in the first row with its predecessor to get the number in the second row; see how:
3*2 = 6
8*7 = 56
10*9 = 90
2*1 = 2
5*4 = 20
1*0 = 0

Therefore 5 (option ‘3’) is the answer

OR; Square the number in the first row and subtract the number itself from it to get the number in the second row; see how:
3^2 – 3 = 6
8^2 – 8 = 56
10^2 – 10 = 90
2^2 – 2 = 2
5^2 – 5 = 20
1^2 – 1 = 0

Therefore 5 (option ‘3’) is the answer.

#### QUERY 76

An Ssc Aspirant

1^3 – 1 = 0
2^3 – 3 = 5
3^3 – 5 = 22
4^3 – 7 = 57 (option ‘B’)

#### QUERY 77

3       4       6
5       7       3
1       2       7
35  69       ?

82
94
84
42

MAHA GUPTA
Add the squares of all the numbers of the first three rows to get the number in the last row; see how

3^2 + 5^2 + 1^2 = 35
4^2 + 7^2 + 2^2 = 69

Therefore 6^2 + 3^2 + 7^2 = 94 (option ‘2’)

#### QUERY 78

130 : 154 :: 178 : ?

24
180
204
206

MAHA GUPTA
(11^2) + 9 = 130
(12^2) +10 = 154

Like above
(13^2) + 9 = 178
(14^2) +10 = 206 (option ‘4’)

#### QUERY 79

Find odd one out
1, 5, 9, 15, 25, 37, 49

MAHA GUPTA
15 as it should be 17; The pattern of difference between numbers is :
4, 4
8, 8
12, 12

#### QUERY 80

Find odd one out
445, 221, 109, 46, 25, 11, 4

Replace 46 by 53; see how
4 + 7*1 = 11
11 + 7*2 = 25
25 + 7*4 = 53 (desired number)
53 + 7*8 = 109
109 + 7*16 = 221
221 + 7*32 = 445

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