# QUESTIONS ON REASONING (PART-10)

#### QUESTIONS ON REASONING (PART-10)

Most of these questions are taken from the previous examinations conducted by the Staff Selection Commission (SSC) of the General Intelligence and Reasoning section of the following exams as well as other similar exams. They are all solved and supported by detailed explanation.

1. Combined Graduate Level (CGL) Exam Tier-I

2. Combined Higher Secondary (10+2) Exam (CHSL) Tier-I

3. SI in Delhi Police and CPO Exam Tier-I

4. Stenographers Exam

5. Grade-II DASS Exam conducted by Delhi Staff Subordinate Services (DSSSB)

#### QUERY 181

**MAHA GUPTA**

Pattern of each column

4/2, 5 + 1, 7 – 1; 266

6/2, 8 + 1, 9 – 1, 398

So the required number

8/2, 3 + 1, 6 – 1, 445 (option ‘A’)

QUERY 182

**KUMAR SAURABH**

[(7 – 3) + (4 + 6)]*3 = 42

[(9 – 5) + (8 + 7)]*3 = 57

Therefore the required number

[(6 – 2) + (8 + 0)]*3 = 36

QUERY 183

**3, 8, 27, 112, ?, 3396**

**MEGHA DIXIT**

Pattern

3*2 + 2 = 8

8*3 + 3 = 27

27*4 + 4 = 112

112*5 + 5 = 565 (answer)

565*6 + 6 = 3396

QUERY 184

**MAHA GUPTA**

Each number is representing the number of the sides of the box in which it falls, see how

The box having the number 3 has 3 sides

Both the boxes having the number have 5 three sides each

The box having the number 8 has 8 sides

Therefore the required number will be 7 as that box has 7 sides (answer)

QUERY 185

**Find odd one**

** 36**

** 61**

** 84**

** 108**

**MAHA GUPTA**

61 (option ‘2’) as it’s a prime number whereas the others are composite.

QUERY 186

**25 4 57**

** 9 71 6**

** 52 ? 23**

**NIHARIKA MISHRA**

You see that total of first and the last column each is 86

Therefore the required number

4 + 71 + ? = 86

==> ? = 11 (answer)

QUERY 187

**0, 2, 6, 12, 20, 30, 42, ?**

**MAHA GUPTA**

Square natural numbers from the beginning and subtract that number itself from the result, see how

1^2 – 1 = 0

2^2 – 2 = 2

3^2 – 3 = 6

4^2 – 4 = 12

5^2 – 5 = 20

6^2 – 6 = 30

7^2 – 7 = 42

Therefore the required number

8^2 – 8 = 56 (answer)

QUERY 188

**5 : 10 :: ? : 40**

15

20

30

25

**MAHA GUPTA**

The first number on LHS is half the second number

Therefore the required number = 40/2 = 20 (option ‘2’)

QUERY 189

**98 – 64 = 14, 86 – 23 = 27, 40 – 11 = ?**

6

7

8

9

**SUBHASH CHANDRA**

Multiply the subtraction of the sum of the digits of the numbers on LHS by 2, 3, 4 respectively, see how

[(9+8) – (6+4)]*2 = (17 -10)*2 = 14

[(8+6) – (2+3)]*3 = (14 – 5)*3 = 27

Therefore the required number

[(4+0) – (1+1)]*4 = (4 – 2)*4 = 8 (option ‘3’)

QUERY 190

**55, 64, 73, 19, ?**

91

63

72

22

**DUSHYANT KUMAR**

Sum of digit of every number is 10, so the required number is 91 (option ‘1’)

QUERY 191

**8 12 13**

** 6 5 10**

** 2 8 ?**

** 4 15 18**

**SHIV KISHOR**

4 – (8 – 6) = 2

15 – (12 – 5) = 8

Therefore the required number

18 – (13 – 10) = 15 (answer)

QUERY 192

**Find odd one out**

** REAP**

** RARE**

** TORE**

** TEAR**

**MAHA GUPTA**

RARE (option ‘2’. The consonant is repeating here whereas the constants in others are different.

QUERY 193

**-1, 2, 7, 14, ?**

**MAHA GUPTA**

Prime numbers starting from 3 have been added to get the next number; see how

-1 + 3 = 2

2 + 5 = 7

7 + 7 = 14

Therefore the required number

14 + 11 = 25 (answer)

QUERY 194

**1, 6, 15, ?, 45, 66, 91**

25

26

27

28

**ADITYA CHOUDHARY**

1 + 5 = 6

6 + 9 = 15

15 + 13 = 28 (option ‘4’)

28 + 17 = 45

45 + 21 = 66

66 + 25 = 91

QUERY 195

**Find the number which does not belong to the series**

** 8, 13, 21, 32, 47, 63, 83**

13

47

32

63

**MAHA GUPTA**

Each number is more by 3 of the difference of its two previous numbers, see how

21 = 13 + {3 + (13 – 8)}

32 = 21 + {3 + (21 – 13)}

So the next should be 32 + {3 + (32 – 21) = 46 (so answer is 47, option ‘2’)

63 = 46 + {3 + (46 – 32)

83 = 63 + {3 + (63 – 46)

QUERY 196

**SHIV KISHOR**

3+5+6

=> 3*5, 3*6, (3*5 + 3*6 – 6)

=> 15, 18, 27

=> 151872 (Last two digits are reversed)

5+5+6

=> 5*5, 5*6, (5*5 + 5*6 – 6)

=> 25, 30, 49

=> 253094

5+6+7

=> 5*6, 5*7, (5*6 + 5*7 – 7)

=> 30, 35, 58

=> 303585

—-

5+5+3

=> 5*5,5*5,(5*5 +5*5-3)

=> 25,25,47

=> 252574

Therefore the required number

9+4+7

=> 9*4, 9*7, (9*4 + 9*7 – 7)

=> 36, 63, 92

=> 366329

QUERY 197

**VIPIN KUMAR**

5*1 + 6*1 = 11

6*4 + 3*2 = 30

Therefore the required number

3*5 + 4*3 = 27 (option ‘D’)

QUERY 198

**If**

** 7 + 4 = 823**

** 9 + 6 = 453**

** 5 + 7 = 532**

** then, 8 + 7 = ?**

**MAHA GUPTA**

Reverse the product of the numbers of LHS and put their difference on the rightmost side to get the number on RHS, see how

7*4 = 28; 7 – 4 = 3 ==> 823

9*6 = 54; 9 – 6 = 3 ==> 453

5*7 = 35; 7 – 5 = 2 ==> 532

Therefore the required number

8*7 = 56; 8 – 7 = 1 ==> 651 (answer)

QUERY 199

**13, 35, 57, 79, 911, ?**

**MAHA GUPTA**

2 is added to the left digit of every number, and again 2 is added to the number formed by rest of the digits; see how

1+2 = 3; 3+2 = 5 => 35

3+2 = 5; 5+2 = 7 => 57

5+2 = 7; 7+2 = 9 => 79

7+2 = 9; 9+2 = 11 => 911

Therefore the required number

9+2 = 11; 11+2 = 13 => 1113 (answer)

QUERY 200

**600, 125, 30, ? , 7.2 , 6.44, 6.288**

**SHIV KISHOR**

600 – 475/1 = 125

125 – (475/5) = 30

30 – (475/25) = 11 (The required number)

11 – (475/125) = 7.2

7.2 – (475/625) = 6.4

6.4 – (475/3125) = 6.288