REASONING

QUESTIONS ON REASONING (PART-10)

QUESTIONS ON REASONING (PART-10)

Most of these questions are taken from the previous examinations conducted by the Staff Selection Commission (SSC) of the General Intelligence and Reasoning section of the following exams as well as other similar exams. They are all solved and supported by detailed explanation.

1. Combined Graduate Level (CGL) Exam Tier-I

2. Combined Higher Secondary (10+2) Exam (CHSL) Tier-I

3. SI in Delhi Police and CPO Exam Tier-I

4. Stenographers Exam

5. Grade-II DASS Exam conducted by Delhi Staff Subordinate Services (DSSSB)

QUERY 181

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MAHA GUPTA

Pattern of each column
4/2, 5 + 1, 7 – 1; 266

6/2, 8 + 1, 9 – 1, 398

So the required number
8/2, 3 + 1, 6 – 1, 445 (option ‘A’)


QUERY 182

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KUMAR SAURABH

[(7 – 3) + (4 + 6)]*3 = 42
[(9 – 5) + (8 + 7)]*3 = 57

Therefore the required number
[(6 – 2) + (8 + 0)]*3 = 36


QUERY 183

3, 8, 27, 112, ?, 3396

MEGHA DIXIT
Pattern
3*2 + 2 = 8
8*3 + 3 = 27
27*4 + 4 = 112
112*5 + 5 = 565 (answer)
565*6 + 6 = 3396


QUERY 184

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MAHA GUPTA

Each number is representing the number of the sides of the box in which it falls, see how
The box having the number 3 has 3 sides
Both the boxes having the number have 5 three sides each
The box having the number 8 has 8 sides

Therefore the required number will be 7 as that box has 7 sides (answer)


QUERY 185

Find odd one
36
61
84
108

MAHA GUPTA
61 (option ‘2’) as it’s a prime number whereas the others are composite.


QUERY 186

25     4     57
9      71     6
52    ?     23

NIHARIKA MISHRA
You see that total of first and the last column each is 86

Therefore the required number
4 + 71 + ? = 86
==> ? = 11 (answer)


QUERY 187

0, 2, 6, 12, 20, 30, 42, ?

MAHA GUPTA
Square natural numbers from the beginning and subtract that number itself from the result, see how
1^2 – 1 = 0
2^2 – 2 = 2
3^2 – 3 = 6
4^2 – 4 = 12
5^2 – 5 = 20
6^2 – 6 = 30
7^2 – 7 = 42

Therefore the required number
8^2 – 8 = 56 (answer)


QUERY 188

5 : 10 :: ? : 40

15
20
30
25

MAHA GUPTA
The first number on LHS is half the second number

Therefore the required number = 40/2 = 20 (option ‘2’)


QUERY 189

98 – 64 = 14, 86 – 23 = 27, 40 – 11 = ?

6
7
8
9

SUBHASH CHANDRA
Multiply the subtraction of the sum of the digits of the numbers on LHS by 2, 3, 4 respectively, see how
[(9+8) – (6+4)]*2 = (17 -10)*2 = 14
[(8+6) – (2+3)]*3 = (14 – 5)*3 = 27

Therefore the required number
[(4+0) – (1+1)]*4 = (4 – 2)*4 = 8 (option ‘3’)


QUERY 190

55, 64, 73, 19, ?

91
63
72
22

DUSHYANT KUMAR
Sum of digit of every number is 10, so the required number is 91 (option ‘1’)


QUERY 191

8     12     13
6     5      10
2     8       ?
4    15     18

SHIV KISHOR
4 – (8 – 6) = 2
15 – (12 – 5) = 8

Therefore the required number
18 – (13 – 10) = 15 (answer)


QUERY 192

Find odd one out
REAP
RARE
TORE
TEAR

MAHA GUPTA
RARE (option ‘2’. The consonant is repeating here whereas the constants in others are different.


QUERY 193

-1, 2, 7, 14, ?

MAHA GUPTA
Prime numbers starting from 3 have been added to get the next number; see how
-1 + 3 = 2
2 + 5 = 7
7 + 7 = 14

Therefore the required number
14 + 11 = 25 (answer)


QUERY 194

1, 6, 15, ?, 45, 66, 91

25
26
27
28

ADITYA CHOUDHARY
1 + 5 = 6
6 + 9 = 15
15 + 13 = 28 (option ‘4’)
28 + 17 = 45
45 + 21 = 66
66 + 25 = 91


QUERY 195

Find the number which does not belong to the series
8, 13, 21, 32, 47, 63, 83

13
47
32
63

MAHA GUPTA
Each number is more by 3 of the difference of its two previous numbers, see how
21 = 13 + {3 + (13 – 8)}
32 = 21 + {3 + (21 – 13)}

So the next should be 32 + {3 + (32 – 21) = 46 (so answer is 47, option ‘2’)

63 = 46 + {3 + (46 – 32)
83 = 63 + {3 + (63 – 46)


QUERY 196

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SHIV KISHOR

3+5+6
=> 3*5, 3*6, (3*5 + 3*6 – 6)
=> 15, 18, 27
=> 151872 (Last two digits are reversed)

5+5+6
=> 5*5, 5*6, (5*5 + 5*6 – 6)
=> 25, 30, 49
=> 253094

5+6+7
=> 5*6, 5*7, (5*6 + 5*7 – 7)
=> 30, 35, 58
=> 303585

—-
5+5+3
=> 5*5,5*5,(5*5 +5*5-3)
=> 25,25,47
=> 252574

Therefore the required number
9+4+7
=> 9*4, 9*7, (9*4 + 9*7 – 7)
=> 36, 63, 92
=> 366329


QUERY 197

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VIPIN KUMAR

5*1 + 6*1 = 11
6*4 + 3*2 = 30

Therefore the required number
3*5 + 4*3 = 27 (option ‘D’)


QUERY 198

If
7 + 4 = 823
9 + 6 = 453
5 + 7 = 532
then, 8 + 7 = ?

MAHA GUPTA
Reverse the product of the numbers of LHS and put their difference on the rightmost side to get the number on RHS, see how
7*4 = 28; 7 – 4 = 3 ==> 823
9*6 = 54; 9 – 6 = 3 ==> 453
5*7 = 35; 7 – 5 = 2 ==> 532

Therefore the required number
8*7 = 56; 8 – 7 = 1 ==> 651 (answer)


QUERY 199

13, 35, 57, 79, 911, ?

MAHA GUPTA
2 is added to the left digit of every number, and again 2 is added to the number formed by rest of the digits; see how

1+2 = 3; 3+2 = 5 => 35
3+2 = 5; 5+2 = 7 => 57
5+2 = 7; 7+2 = 9 => 79
7+2 = 9; 9+2 = 11 => 911

Therefore the required number
9+2 = 11; 11+2 = 13 => 1113 (answer)


QUERY 200

600, 125, 30, ? , 7.2 , 6.44, 6.288

SHIV KISHOR
600 – 475/1 = 125
125 – (475/5) = 30
30 – (475/25) = 11 (The required number)
11 – (475/125) = 7.2
7.2 – (475/625) = 6.4
6.4 – (475/3125) = 6.288

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Maha Gupta

Maha Gupta

Founder of www.examscomp.com and guiding aspirants on SSC exam affairs since 2010 when objective pattern of exams was introduced first in SSC. Also the author of the following books:

1. Maha English Grammar (for Competitive Exams)
2. Maha English Practice Sets (for Competitive Exams)